log[x(x-1)]=2

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Solution for log[x(x-1)]=2 equation: 


Simplifying
log[x(x + -1)] = 2

Reorder the terms:
glo[x(-1 + x)] = 2
glo[(-1 * x + x * x)] = 2
glo[(-1x + x2)] = 2
[-1x * glo + x2 * glo] = 2
[-1glox + glox2] = 2

Solving
-1glox + glox2 = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + -1glox + glox2 = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -1glox + glox2 = 0

The solution to this equation could not be determined.

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